Hi, basically I have this snippet some of which I am trying to move into a function. In its current form it works OK, but when I try to call for it within my function it does not :
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given in C:\xampp\htdocs\1\assets\includes\memberfunc.php on line 18
Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, null given in C:\xampp\htdocs\1\login.php on line 106
Acess denied, wrong username or password?
Here's the function.
function logcon($user, $password )
{
$esc_user = mysqli_real_escape_string($this->conn, $user);
$esc_password = mysqli_real_escape_string($this->conn,$password);
$sql = "select * all from users where username ='{$user}' AND password='{$password}'";
$result = mysqli_query($this->conn, $sql);
$row = mysqli_fetch_array($this->conn, $result);
return $row;
}Here's the old, working code.
if(isset($_POST['submit'])){
$user=$_POST['user'];
$password=$_POST['password'];
//To ensure that none of the fields are blank when submitting the form if
if(isset($_POST['user']) && isset($_POST['password']))
{
$user = stripslashes($user);
$password = stripslashes($password);
$db1=new dbmember();
$db1->openDB();
$sql="SELECT * FROM users WHERE username='{$user}' AND password='{$password}'";
$result=$db1->logcon($user, $password);
$row=mysqli_fetch_array($result);
if($row[0]==1)
{
session_start();
$_SESSION['user'] = $user;
$_SESSION['password'] = $password;
$_SESSION['loggedin'] = "true";
header("location:index.php");
}Any help on this would be fantastic. I'm pretty stuck.