I am attempting to setup a profile page based on the information that the user signs up with.
(I am following a video online, the code matches but he is on a local server i am using a hosted server idk if issue)
On my profile.php page I am receiving the warning :
Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 5 in /home/content/80/11355280/html/core/function/users.php on line 88
On my profile page I am trying to use function : user_id_from_username. This function is currently working with my login.
However on profile.php
<?php
include 'include/widgets/tabletop.php';
if (isset($_GET['username']) === true && empty($_GET['username']) === false) {
$username = $_GET['username'];
$user_id = user_id_from_username($username);
echo $user_id;
} else {
header('Location: index.php');
exit();
}
include 'include/widgets/tablebot.php';
?>
On line 14 I am calling the function I created and attempting to echo out the user id. When I attempt this I receive the warning.
The function is held in users.php and is included on the page.
users.php
function user_id_from_username($username) {
$username = sanitize($username);
return mysql_result(mysql_query("SELECT `user_id` FROM `users` WHERE `username` = '$username'"), 0, 'user_id');
}
if I would put a or die at the end of the return mysql_result I get the same error but a different index.
Warning: mysql_result() [function.mysql-result]: Unable to jump to row 0 on MySQL result index 12 in /home/content/80/11355280/html/core/function/users.php on line 88
Would an if ( something > 0 ) fix this and how?