Display image from sql number value

Okay, I thought I had this down to what I'm trying to do. But I can't find where I'm going wrong. I promise I searched the best I could, but I can't find specifically where the error (500) is coming from. This is what I added, without it, I get no error, but I get no echo of what I'm wanting either.

 echo "<tr><td><div align=\"left\"><font face=\"Verdana, Arial, Helvetica, sans-serif\" color=\"CCCCCC\" size=\"2\">This Review Is About:</font></br><font face=\"Verdana, Arial, Helvetica, sans-serif\" color=\"FF6633\" size=\"4\"><b>{$band['Name']}</b></font></br><img src=\"http://www.inthisreview.com/Misc/tablespacersm01.png\"></br><font face=\"Verdana, Arial, Helvetica, sans-serif\" color=\"CCCCCC\" size=\"2\">Review Posted:</br></font><font face=\"Verdana, Arial, Helvetica, sans-serif\" color=\"FFFFFF\" size=\"2\"> ".date("F j, Y g:i a", strtotime($band["timestamp"]))."</font>

</br><img src=\"http://www.inthisreview.com/Misc/tablespacersm01.png\"></br>
<font face=\"Verdana, Arial, Helvetica, sans-serif\" color=\"FF0000\" size=\"2\">ITR Rating:</font>

if($band['rating']=='0'){
 echo "<img src='../ratings/0star.png'/>";
}
elseif($band['rating']=='1'){
 echo "<img src='../ratings/1star.png'/>";
}
elseif($band['rating']=='2'){
 echo "<img src='../ratings/2star.png'/>";
}
elseif($band['rating']=='3'){
 echo "<img src='../ratings/3star.png'/>";
}
elseif($band['rating']=='4'){
 echo "<img src='../ratings/4star.png'/>";
}
elseif($band['rating']=='5'){
 echo "<img src='../ratings/5star.png'/>";
}



</td>";

People on here have been great with help, and it's always very much appreciated.